I would like to get all the text/numbers that appear after the equals sign such that this input
"Input: m = 2, n = 3, indices = [[0,1],[1,1]]"
Would return this output:
[2,3, [[0,1],[1,1]] ]
This is what I have tried:
eachEx.match(/= (.+)/)[1]
However this returns:
2, n = 3, indices = [[0,1],[1,1]]
I have thought of splitting the string and iterating through each element, passing it through the match I have. However, the problem is that I would lose the ability to know whether or not the element in question was meant to be a string or an integer or an array. I need to know this information
>Solution :
I won’t be surprised if you end up needing to write a simple parser for this, rather than a single regex. But the specific example given can be done with a single regex. It’s just that I suspect when you throw more examples at it, it’ll become too complicated.
If the thing that makes the , a delimiter after the 2 and 3 but not in the final match is that the final match is wrapped in [___], then you can use an alternation to adjust what characters are allowed in the capture:
/= (\[[^=]+\]|[^=,]+)/
That says that if the text starts with [ and ends with ], match all non-= inside it. Otherwise, match all non-= and non-,.
Then, to get all the matches, add a g flag and use matchAll, then post-process the iterable you get from it to extract the capture groups:
const eachEx = "Input: m = 2, n = 3, indices = [[0,1],[1,1]]";
const match = eachEx.matchAll(/= (\[[^=]+\]|[^=,]+)/g);
console.log(Array.from(match, ([, capture]) => capture));As an example of a string that would be parsed incorrectly by that, consider "a = [3, [2, ], b = 3", which gives us the array [ "[3, [2, ]", "3" ] when probably it should be an error:
const eachEx = "Input: a = [3, [2, ], b = 3";
const match = eachEx.matchAll(/= (\[[^=]+\]|[^=,]+)/g);
console.log(Array.from(match, ([, capture]) => capture));Hence the warning above that you may need to write a simple parser instead.