Regex to remove characters after multiple white spaces

November 9, 2021

Hi all I’ve got and input strings:

list_of_strings = ["apple", "orange ca", "pear  sa", "banana    sth"]

And I want to remove everything after multiple white spaces (more than 1), so end result is:

final_list_of_strings = ["apple", "orange ca", "pear", "banana"]

I’ve tried regex:

import re

regex_expression = r"(.*\s?)(\s{2,}.*)"

for name in list_of_strings:
    regex_matching_groups = re.findall(regex_expression, name)
    if regex_matching_groups:
    name = regex_matching_groups[0][0]

but fails on multiple spaces … Thank you for help!

>Solution :

You can use re.sub in a list comprehension:

import re
list_of_strings = ["apple", "orange ca", "pear  sa", "banana    sth"]
list_of_strings = [re.sub(r'\s{2}.*', '', x, flags=re.S) for x in list_of_strings]
print(list_of_strings)
# -> ['apple', 'orange ca', 'pear', 'banana']

See the Python demo.

The \s{2}.* regex matches two whitespace chars and then the rest of the string (even if there are line break chars due to re.S flag).