Remove a string using Ternary operation in JavaScript

I have something like this in my console: How can I take out the [object Object] from my output?

I want the output printed without the [Object Object]. Probably using a ternary operation?

id:4fe2ce6467ca126064231husklpjahjjkk 
url:http://8000/v1/data/country/
type:country
name:South Africa
legal:[object Object]
  text:Data is supplied by Government
  link:https://en.wikipedia.org/

This is my code:

const GetData = (obj, step) => {

    let padSpace = ""

    for (let j=0; j < step; j++) {
      padSpace += ''
    }

    for (let k in obj) {
      console.log(padSpace + k + ':' + obj[k])
      if (typeof(obj[k]) === "object") {
        if (Array.isArray(obj[k])) {
          obj[k].forEach(element => {
              if (typeof(element === "object")) {
                GetData(element, step + 1);
              } else {
                console.log(padSpace + element)
              }
            }
          );
        } else {
          GetData(obj[k], step + 1);
        }
      } else {}
    }

I want something like:

>Solution :

The following test will always pass because typeof true and typeof false are both "boolean" which is truthy.

if (typeof(element === "object")) {

Try

if (typeof element === "object") {

I have no idea why you are talking about a ternary operation.

To avoid the [object Object] you can move the existing console.log and add another one as shown:

for (let prop in entity) {  
  if (typeof entity[prop] === "object") {
    console.log(padString + prop + ':');
    if (Array.isArray(entity[prop])) {
      entity[prop].forEach(element => {
        if (typeof element === "object") {
          formatData(element, level + 1);
        } else {
          console.log(padString + element)
        }
      });
    } else {
      formatData(entity[prop], level + 1);
    }
  } else {
    console.log(padString + prop + ':' + entity[prop])
  }
}