remove element based on values found in another element xslt-3

The following works:

<xsl:stylesheet version="1.0"
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>
    
     <xsl:template match="node()|@*">
      <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
      </xsl:copy>
     </xsl:template>
    
     <xsl:template match=
     "*[ID='579']/EMAIL"/>
    </xsl:stylesheet>

But i need to remove the email element based on many ID values
something like below is not working:

"*[ID='579|987|1023']/EMAIL"/>

How would you do it i a more cleverway with xslt-3?

>Solution :

Use a string sequence parameter e.g.

<xsl:param name="ids" as="xs:string*" select="'579', '987', '1023'"/>

then you can use match="*[ID = $ids]/EMAIL":

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="3.0"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  exclude-result-prefixes="#all">

  <xsl:mode on-no-match="shallow-copy"/>

  <xsl:param name="ids" as="xs:string*" select="'579', '987', '1023'"/>

  <xsl:template match="*[ID = $ids]/EMAIL"/>

</xsl:stylesheet>

Or pass in a single string separated with | and use match="*[ID = tokenize($ids, '\|')]/EMAIL":

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="3.0"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  exclude-result-prefixes="#all">

  <xsl:mode on-no-match="shallow-copy"/>

  <xsl:param name="ids" as="xs:string" select="'579|987|1023'"/>

  <xsl:template match="*[ID = tokenize($ids, '\|')]/EMAIL"/>

</xsl:stylesheet>