Removing an element from a list by index without returning the deleted element

simply put, I just want an alternative to .pop that does not return the removed element and also takes an index for parameters.
To give an example, I enter this code:

[1, 2, 3].pop(0)

but it gives me this as an output:

[1]

what I want as an output is [2, 3] and not [1].
is there a simple way of doing this?

>Solution :

You can also use list slicing method.

print([1,2,3][1:])