repeat a sequence of numbers N times and incrementally increase the values in the sequence Python

I have a number sequence as below

sequence = (0,0,1,1,1,1)

I want the number sequence to repeat a specified number of times but incrementally increase the values within the sequence

so if n= 3 then the sequence would go 1,1,2,2,2,2,3,3,4,4,4,4,5,5,6,6,6,6

I can make a sequence like below but the range function is not quite right in this instance

n = 3
CompleteSequence =  [j + k for j in range(0, n, 2) for k in sequence]
CompleteSequence 
[0, 0, 1, 1, 1, 1, 2, 2, 3, 3, 3, 3]

I have tried itertools

import itertools
sequence = (0,0,1,1,1,1)
n=3
list1 = list(itertools.repeat(sequence,n))
list1

[(0, 0, 1, 1, 1, 1), (0, 0, 1, 1, 1, 1), (0, 0, 1, 1, 1, 1)]

How can I go I achieve the pattern I need? a combination of range and itertools?

>Solution :

You can achieve this pattern with range() and an increment variable:

sequence = (0,0,1,1,1,1)
n = 3

CompleteSequence = []
increment = 1
for i in range(1, n+1):
    for j in sequence:
        CompleteSequence.append(j + increment)
    increment += 2

CompleteSequence now holds:

[1, 1, 2, 2, 2, 2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 6, 6, 6]