Replace key in a senetence with its value

I have a dictionary and a list

dict1= {'good':'bad','happy':'sad','pro':'anti'}

list1=['she is good','this is a product','they are pro choice']

newlist=[]
for index, data in enumerate(list1):
    for key, value in dict1.items():
        if key in data:
            list1[index]=data.replace(key, dict1[key])
            newlist.append(list1[index])

The output I get is
['she is bad','this is a antiduct','they are anti choice']

desired output is
['she is bad','this is a product','they are anti choice']

How can I fix it? It is replacing the pro of prodcut too. I only want it to replace pro when it exists as an independent word.

>Solution :

One option would be to split each phrase and do the substitution with a straight get on the dictionary, rather than a replace:

>>> dict1= {'good':'bad','happy':'sad','pro':'anti'}
>>> list1={'she is good','this is a product','they are pro choice'}
>>> [' '.join(dict1.get(word, word) for word in phrase.split()) for phrase in list1]
['this is a product', 'she is bad', 'they are anti choice']

Note that this will not preserve whitespace in the phrase, nor will it handle punctuation very well. re and itertools.groupby would be useful tools to handle those more complex cases.