Returning the Key with the highest Value from a List of Dictionaries

In this problem, you’ll do the same thing, but with a more
complex data structure. Your function should be called
most_active, and it should have one parameter.

Instead of a dictionary, your parameter is a list of
dictionaries. Every dictionary in the list will have exactly
two keys: ‘name’ and ‘days_active’. Your goal, as before,
is to return the name of the most active student.

Some of the code you wrote on the previous problem will be
reusable, but you’ll need to modify it.

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Hint: you do NOT need to iterate over the keys in the
dictionaries inside the lists. You can always just access
the_dict["name"] and the_dict["days_active"] directly.
Your only loop should be the loop over the list.

#Add your code here!

def most_active(the_list):
    max_active = (max(the_list, key=lambda x: (["days_active"])))
    return max_active

    

Below are some lines of code that will test your function.
You can change the value of the variable(s) to test your
function with different inputs.

If your function works correctly, this will originally
print:
Chopra, Deepak

the_list = [{"name": "Joyner, David", "days_active": 14},
            {"name": "Chopra, Deepak", "days_active": 22},
            {"name": "Winfrey, Oprah", "days_active": 17}]
print(most_active(the_list))

Currently my code returns the following: {'name': 'Joyner, David', 'days_active': 14}
I have been working on this since yesterday and have tried many "solutions" but this is the closest I have gotten. Also, I have searched and searched on every conceivable forum and can’t seem to figure this out…any and all help is appreciated.

>Solution :

This works:

def most_active(the_list):
    return max(the_list, key=lambda x: x["days_active"])