i am new to scala and hate regex 😀
cuurently i am debuggig a piece of code
def validateReslutions(reslutions: String): Unit = {
val regex = "(\\d+-\\d+[d,w,m,h,y],?)*"
if (!reslutions.matches(regex)) {
throw new Error("no match")
} else {
print("matched")
}
}
validateReslutions(reslutions = "(20-1w,100-1w)")
}
the problem is it produces no match for this input , so how to correct the regex to match this input
>Solution :
Your (20-1w,100-1w) string contains a pair of parentheses at the start and end, and the rest matches with your (\d+-\d+[d,w,m,h,y],?)* regex. Since String#matches requires a full string match, you get an exception.
Include the parentheses patterns to the regex to avoid the exception:
def validateReslutions(reslutions: String): Unit = {
val regex = """\((\d+-\d+[dwmhy],?)*\)"""
if (!reslutions.matches(regex)) {
throw new Error("no match")
} else {
print("matched")
}
}
validateReslutions(reslutions = "(20-1w,100-1w)")
// => matched
See the Scala demo.
Note the triple quotes used to define the string literal, inside which you can use single backslashes to define literal backslash chars.
Also, mind the absence of commas in the character class, they match literal commas in the text, they do not mean "or" inside character classes.