Searching for a number in a given array using pointers

I need to create a program that searches for a user inserted number from an array using pointers. This is my current code

#include <iostream>
using namespace std;

void FindNumber(int *ptrArr, int size, int *ptr1) {
    for (int *p = ptrArr; p < ptrArr + size; ++p) {
        if (ptrArr[*p] == *ptr1) {
            cout << "Number (" << *ptr1 << ") found in the array with an index of: " << *p;
            break;
        }

        if (*p == size) {
            cout  << "No such number in given array\n";
        } 

    }
}

int main () {
    int numbers[10] = {5, 4, 7, 10, 24, 15, 8, 2, 9, 13};
    int num;

    cout << "What number do you want to search for?\n";
    cin >> num;

    FindNumber(numbers, sizeof(numbers) / sizeof(int), &num);
    return 0;
}

The problem is with for loop, but I don’t know what it is
Sometimes it finds the number with right index, sometimes it doesn’t find it even though there is that particular number in the array, sometimes it finds the number but outputs the wrong index

What number do you want to search for?
7
No such number in given array
Number (7) found in the array with an index of: 2

What number do you want to search for?
5
No such number in given array

Tried changing the for loop on my own but no successo. Hoping for some help.

>Solution :

You have 2 small typos in your code.

-No need to index the array with "*p"

-The index need to be calculated by subtracting p from the original pointer.

Please see here the fixed code:

#include <iostream>
using namespace std;

void FindNumber(int* ptrArr, int size, int* ptr1) {
    for (int* p = ptrArr; p < ptrArr + size; ++p) {
        if (*p == *ptr1) {
            cout << "Number (" << *ptr1 << ") found in the array with an index of: " << (p-ptrArr);
            return;
        }
    }
    cout << "No such number in given array\n";

}

int main() {
    int numbers[10] = { 5, 4, 7, 10, 24, 15, 8, 2, 9, 13 };
    int num;

    cout << "What number do you want to search for?\n";
    cin >> num;

    FindNumber(numbers, sizeof(numbers) / sizeof(int), &num);
    return 0;
}