sed replace regex match group

I’ve a file:

import "aaaa/bbbb.ccc";
import "dddd/eeee.ccc";
import "fffff/ggg/hhhh.ccc";

BLBLBL
BL2BL2BL

And I want to replace the path of the import like this:

import "ooooo/bbbb.ccc";
import "ooooo/eeee.ccc";
import "ooooo/hhhh.ccc";

BLBLBL
BL2BL2BL

I’ve my regex with a match group of the part I want to replace:
import \"([a-zA-Z]+\/|[a-zA-Z]+\/+[a-zA-Z]+\/)[a-zA-Z]+\.ccc\"

But I don’t know how to use it with sed to replace it with ooooo/

>Solution :

You can use

sed -E 's,^(import ").*/,\1ooooo/,' file > newfile

Details:

• -E – enabling POSIX ERE syntax
• ^(import ").*/ – matches start of string (^), import ", and then one or more chars until the last /
• \1ooooo – replaes with Group 1 value plus ooooo.

The , char is used as a regex delimiter chars, so no need to escape / chars.

See the online demo:

#!/bin/bash
s='import "aaaa/bbbb.ccc";
import "dddd/eeee.ccc";
import "fffff/ggg/hhhh.ccc";

BLBLBL
BL2BL2BL'
sed -E 's,^(import ").*/,\1ooooo/,' <<< "$s"

Output:

import "ooooo/bbbb.ccc";
import "ooooo/eeee.ccc";
import "ooooo/hhhh.ccc";

BLBLBL
BL2BL2BL