Selenium + Python – Checking image via execute_script

I need to verify if a image is shown on page with selenium in python.
For example lets check logo in left upper corner of the https://openweathermap.org/ page.
I use execute_script and my code is:

def test_image(driver):
    driver.get('https://openweathermap.org/')
    time.sleep(10)
    image = driver.find_element(By.CSS_SELECTOR, "#first-level-nav > li.logo > a > img")
    print(image)
    print(driver.execute_script("return (typeof arguments[0].naturalWidth!=\"undefined\");", image))
    print(driver.execute_script("return (typeof arguments[0].naturalWidth>0);", image))
    print(driver.execute_script("return (arguments[0].naturalWidth);", image))

And I got this results:

True
False
431

Why typeof arguments[0].naturalWidth>0 is False when arguments[0].naturalWidth is 431? And image rendered correctly on the page.

UPDATE: Correct code is:

print(driver.execute_script("return (arguments[0].naturalWidth>0);", image))

>Solution :

The typeof operator takes precedence over >.

typeof 431     === "number"
"number"   > 0 === false
typeof 431 > 0 === false