Simplify if and else to a single line

August 16, 2022

I want to know if it is possible to reduce this line to a single one

if [[ $(curl --silent --output /dev/null --write-out "%{http_code}" "https://httpbin.org/status/200") -ne 200 ]]; then
  exit 1
else
  exit 0
fi

If the status code of the request was different from 200, exit with error, if it was successfully, exit with 0

>Solution :

curl already has defined exit codes for many situations if you use -f.

A lot of effort has gone into the project to make curl return a usable exit code when something goes wrong and it will always return 0 (zero) when the operation went as planned.

$ curl -f -s http://google.com >/dev/null ; echo $?
0
$ curl -f -s hoop://google.com >/dev/null; echo $?
1
$ curl -f -s http://test.invalid >/dev/null ; echo $?
6
$ curl -f -s http://google.com/invalid >/dev/null ; echo $?
22

To return modified codes (eg. 0 on a 404 as you suggest in a comment), you could do simple boolean manipulation:

$ echo $((
    $(curl -f -s -o /dev/null \
        -w '!(%{http_code}==404)' \
        https://httpbin.org/status/200)
  ))
1
$ echo $((
    $(curl -f -s -o /dev/null \
        -w '!(%{http_code}==404)' \
        https://httpbin.org/status/404)
  ))
0
$

(substitute exit for echo)