Sort array from object based on a property and return the sorted initial object

I have the following object

{
  "object": "list",
  "url": "/v1/prices",
  "has_more": false,
  "data": [
    {
      "id": "price_1KHlU72eZvKYlo2CblI51Z8e",
      "object": "price",
      "active": true,
      "billing_scheme": "per_unit",
      "created": 1642150211,
      "currency": "usd",
      "livemode": false,
      "lookup_key": null,
      "metadata": {},
      "nickname": null,
      "product": "prod_Kxgr3hZDfHnqu1",
      "recurring": {
        "aggregate_usage": null,
        "interval": "month",
        "interval_count": 1,
        "usage_type": "licensed"
      },
      "tax_behavior": "unspecified",
      "tiers_mode": null,
      "transform_quantity": null,
      "type": "recurring",
      "unit_amount": 2,
      "unit_amount_decimal": "2"
    },
    {...},
    {...}
  ]
}

How can I sort the object.data from it based on the unit_amount property and also keep the initial values of the object (url, has_more, …)?

I’ve tried using Ramda, but it’s giving me an new object just with the sorted data.

So I need object.data from the initial object to be sorted and to return the entire object after sorting.

>Solution :

Just simple sorting, for example

const obj = {
  "object": "list",
  "url": "/v1/prices",
  "has_more": false,
  "data": [
    {"unit_amount": 2,},
    {"unit_amount": 1,},
    {"unit_amount": 3,},
    {"unit_amount": 9,},
    {"unit_amount": 5,},
  ]
};

const newObj = { ...obj, data: obj.data.sort((o1, o2) => o1.unit_amount - o2.unit_amount) }; 

console.log(newObj)

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