Sort or remove elements from corresponding list in same way as in reference list

I have two lists in python of same length:

listA = [7,6,3,2,1,4,5]

listB = [a,b,c,d,e,f,g]

is their some way (probably easy function) to sort listA and change the values of listB in the same way. Means

listA_new = [1,2,3,4,5,6,7]

and

listB_new = [e,d,c,f,g,b,a]

same question about remove dublicates. E.g. if I have some list

listC = [1,1,4,4,5,6,7] 

and

listD = [a,b,c,d,e,f,g]

the result should be:

listC_new = [1,4,5,6,7]

and

listD_New = [a,c,e,f,g]

>Solution :

Try this:

[i for j, i in sorted(zip(listA, listB))]

output:

listA = [7, 6, 3, 2, 1, 4, 5]
listB = ["a", "b", "c", "d", "e", "f", "g"]

In [5]: [i for j, i in sorted(zip(listA, listB))]
Out[5]: ['e', 'd', 'c', 'f', 'g', 'b', 'a']

for supporting C and D (removing dupplicates):

sorted(list({j: i for j, i in reversed(sorted(zip(listC, listD)))}.values()))

.values() returns ListD:['a', 'c', 'e', 'f', 'g'] and .keys() returns ListC:[1, 4, 5, 6, 7]