Sorting a list of strings in python on regex isnt actually sorted

So i have a list of strings and im sorting it with:

list = [' R1O-GN | ile: 13 |', ' LXQ2-T | ile: 6 |', ' LXQ2-T | ile: 11 |', ' LXQ2-T | ile: 9 |', ' 4-HWWF | ile: 11 |', ' 4-HWWF | ile: 9 |', ' J-ZYSZ | ile: 12 |', ' UGR-J2 | ile: 8 |']

def ile_sort(elem):
    return re.findall(r'ile: (\d+)',elem)

list = sorted(list, key=ile_sort)

String with 6 should be first and one with 13 last, but the actual result is:

[' LXQ2-T | ile: 11 |', ' 4-HWWF | ile: 11 |', ' J-ZYSZ | ile: 12 |', ' R1O-GN | ile: 13 |', ' LXQ2-T | ile: 6 |', ' UGR-J2 | ile: 8 |', ' LXQ2-T | ile: 9 |', ' 4-HWWF | ile: 9 |']

>Solution :

The problem is that using re.findall() on those list items returns a string within a list, such as this: ["13"]

To combat this, replace your ile_sort() method with this:

def ile_sort(elem):
    return int(re.findall('ile: (\d+)', elem)[0])