I am studying javascript sort method.
So, I want to sort using only sort without filter or map or otherMethod function.
const arr = [1,100,3,5,7,3,2,7, -1]
In the above array, I want the numbers greater than 5 to be sorted first, followed by the smaller numbers in ascending order.
Expected results are:
// [5, 7, 7, 100, -1, 1, 2, 3, 3];
Again, I know how to sort using other methods!
for example
const arr1 = input.filter(num => num >= 5).sort((a, b) => a - b)
const arr2 = input.filter(num => num < 5).sort((a,b) => a - b)
[...arr1, ...arr2]
But I hope to solve it using only the sort method!
please help me
arr.sort((a,b) => {
return (a+5) > b ? 1 : -1
})
but result is :
// [1, 3, -1, 5, 2, 7, 3, 7, 100]
>Solution :
First return the difference between whether one value or the other is less than 5 – proceed to sort numerically (with subtraction) only if that difference is 0 (in which case both values being compared are 5 or above, or both values are less than 5).
const arr = [1,100,3,5,7,3,2,7, -1];
arr.sort((a, b) =>
((b >= 5) - (a >= 5))
|| a - b
);
console.log(arr);