Spread object literal function argument and return shorthand

Is there a shorter way to write this? (Spread object literal argument and return all its properties):

 export const selectUser = ({ fullName, email, userType }) => ({
    fullName,
    email,
    userType,
  }),
);

>Solution :

Assuming (from "return all its properties") the object has exactly these 3 properties, you can:

export const selectUser = obj => ({ ...obj });