for example:
int original_range[] = {1, 2, 3, 4, 5, 6, 7};
int copy_here[7];
std::partition_copy(std::begin(original_range), std::end(original_range),
std::begin(original_range), std::begin(copy_here),
[](int val) { return val >= 4; });
I’m expecting here: original_range = {4, 5, 6, 7, 5, 6, 7} and copy_here = {1, 2, 3, 0, 0, 0, 0}
you can assume that the garbage values stored in copy_here are 0.
>Solution :
Your code invokes UB (Undefined Behavior), and therefore anything can happen.
from std::partition_copy documentation:
Among the input range and the two output ranges, if any two ranges
overlap, the behavior is undefined.
(emphasis is mine)
In your case the first output range overlaps with the input range, and so UB ensues. There is no point rationalising about the program output.