I’m writing a function and this is the last piece of the puzzle, which I thought would be easy to deal with, but after some unsuccessful tinkering with for and while loops, I tried looking it up online and still couldn’t find an answer. I came across some obscure and complex solutions, but I think there should be a more straightforward way to solve this. For example, if I have an array
[1, 2, 3, 5, 7, 9]
And the argument is 10, the function should return 6 (1 + 2 + 3), because the sum of the values should be <= 10 (or whatever number is passed). If the argument is 4, the function should return 3 (1 + 2) and so on.
>Solution :
You can use a for loop:
const arg = 10
const arr = [1, 2, 3, 5, 7, 9]
let res = 0;
const calc = (arr, limit) => {
for (num of arr) {
if (num + res > limit) {
break;
}
res += num;
}
return res;
}
console.log(calc(arr, arg))