Sum the nth value for every key in a python dictionary

EDIT

I have the following dictionary:

dictionary = {'abc': [20, 'john'], 'def': [25, 'jim'], 'ghi': [30, 'jack']}

I would like to sum all of the first values for each key and define it as a variable

Expected answer:

20 + 25 + 30

total_score = 75

>Solution :

You have a dict() having set() assigned to each key. You can not index sets. So considering that the first value in the set will always be the value you want is meaningless.

A workaround is to use list comprehension to build a list() from the set(), that list containing only integer elements. Since you only have one integer per set, then the first index of the list will be the value of interest.

dct = {'abc': {20, 'john'}, 'def': {25, 'jim'}, 'ghi': {30, 'jack'}}

var = 0

for v in dct.values():
    v = [x for x in v if isinstance(x, int)][0]
    var += v
    
print(var)

Output:

75

Edit:

Since the OP edited his question, the new code would be:

dct = {'abc': [20, 'john'], 'def': [25, 'jim'], 'ghi': [30, 'jack']}

var = 0

for v in dct.values():
    var += v[0]
    
print(var)

Or:

var = sum(v[0] for v in dct.values())