Swap values of variables

Good day,

Could you please explain in what order the code executes.

variable_1 = 1
variable_2 = 2

variable_1, variable_2 = variable_2, variable_1

Why is the output 2,1 and not 2,2?
Isn’t variable_1 already become of value 2?

>Solution :

In the code you provided, the output is indeed 2, 1 and not 2, 2. This is because in the third line of the code, you are using a tuple assignment to swap the values of variable_1 and variable_2.

In a tuple assignment, the right-hand side of the assignment is evaluated before the left-hand side. In other words, the values of variable_1 and variable_2 are swapped before they are assigned to the variables on the left-hand side of the assignment. This is why the output is 2, 1 and not 2, 2.

Here is how the code is executed step by step:

1. variable_1 is assigned the value 1.

2. variable_2 is assigned the value 2.

3. The righthand side of the tuple assignment is
   evaluated, which swaps the values of variable_1 and
   variable_2. At this point, variable_1 has the value 2
   and variable_2 has the value 1.

4. The left-hand side of the tuple assignment is evaluated, which assigns the values of variable_1 and variable_2 to the variables on the left-hand side of the assignment. This means that variable_1 is now assigned the value 2 and variable_2 is now assigned the value 1.

To summarize, the tuple assignment is evaluated from right to left, which means that the values of variable_1 and variable_2 are swapped before they are assigned to the variables on the left-hand side of the assignment. This is why the output is 2, 1 and not 2, 2.