SwiftUI: use 'accessibilityIdentifier' only on iOS 14+

Given the following code:

struct CopyButtonStyle: ButtonStyle {

    init() {}

    func makeBody(configuration: Configuration) -> some View {
        let copyIconSize: CGFloat = 24
        return Image(systemName: "doc.on.doc")
            .renderingMode(.template)
            .resizable()
            .frame(width: copyIconSize, height: copyIconSize)
            .accessibilityIdentifier("copy_button")
            .opacity(configuration.isPressed ? 0.5 : 1)
    }
}

I’m getting the following error:

‘accessibilityIdentifier’ is only available in iOS 14.0 or newer use
on iOS 14

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When looking at the accessibilityIdentifier declaration, I found this:

public func accessibilityIdentifier(_ identifier: String) -> ModifiedContent<Self, AccessibilityAttachmentModifier>

Xcode suggest enclosing either the whole button style struct or at least the makeBody function to make it available on iOS 14+.

Is there a way to create an additional function, e.g.:

func addAccessibilityIdentifierIfAvailable(entryParam ??) -> some View

or similar that will return just the same view if the accessibilityIdentifier is not available or return a view with the set identifier if it’s possible to set on that OS version.

>Solution :

Here is a simple way for you:

extension View {
   @ViewBuilder func addAccessibilityIdentifierIfVersionAvailable(identifier: String) -> some View {
        if #available(iOS 14.0, *) { self.accessibilityIdentifier(identifier) }
        else { self } 
    }
}