how can i use the cut() function to create breaks that start at 0? x <- seq(0, 102, length.out = 15) cut(x, breaks = 10) [1] (-0.102,10.2] (-0.102,10.2] (10.2,20.4] (20.4,30.6] (20.4,30.6] (30.6,40.8] (40.8,51] (40.8,51] (51,61.2] (61.2,71.4] (71.4,81.6] (71.4,81.6] [13] (81.6,91.8] (91.8,102] (91.8,102] Levels: (-0.102,10.2] (10.2,20.4] (20.4,30.6] (30.6,40.8] (40.8,51] (51,61.2] (61.2,71.4] (71.4,81.6] (81.6,91.8] (91.8,102] >Solution :… Read More Using cut to create breaks that start at 0