how can i use the cut() function to create breaks that start at 0?
x <- seq(0, 102, length.out = 15)
cut(x, breaks = 10)
[1] (-0.102,10.2] (-0.102,10.2] (10.2,20.4] (20.4,30.6] (20.4,30.6] (30.6,40.8] (40.8,51] (40.8,51] (51,61.2] (61.2,71.4] (71.4,81.6] (71.4,81.6]
[13] (81.6,91.8] (91.8,102] (91.8,102]
Levels: (-0.102,10.2] (10.2,20.4] (20.4,30.6] (30.6,40.8] (40.8,51] (51,61.2] (61.2,71.4] (71.4,81.6] (81.6,91.8] (91.8,102]
>Solution :
Base function pretty outputs pretty numbers. From the documentation, my emphasis.
Compute a sequence of about n+1 equally spaced ‘round’ values which cover the range of the values in x. The values are chosen so that they are 1, 2 or 5 times a power of 10.
x <- seq(0, 102, length.out = 15)
cut(x, breaks = pretty(x, n = 10), include.lowest = TRUE)
#> [1] [0,10] [0,10] (10,20] (20,30] (20,30] (30,40] (40,50]
#> [8] (50,60] (50,60] (60,70] (70,80] (80,90] (80,90] (90,100]
#> [15] (100,110]
#> 11 Levels: [0,10] (10,20] (20,30] (30,40] (40,50] (50,60] (60,70] ... (100,110]
Created on 2022-06-13 by the reprex package (v2.0.1)