Advertisements I have a dictionary in a JSON file and I have loaded that JSON file in my Jupyter Notebook. That dictionary has 3 keys the first key is the stats key which is the basic stats about the dictionary the second key is named questions which is about the questions that were asked in… Read More Wants to convert a key in a dictionary to clean column name
Advertisements I’m having the following dict: {b’one’: b’one’, b’two’: b’two’, b’three’: b’three’} I want to convert this to a json object. I already tried different things with json.dumps, but I only get errors. How can I do this? >Solution : The issue you’re facing is due to the fact that the keys and values in… Read More Python: Convert Bytes inside a dict to json
Advertisements I was exploring different ways to create a dictionary in Python 3 (3.11.1). ChatGPT suggested that I can create a dictionary by using the following syntax: my_dict = dict(‘key1’=’value1’, ‘key2’=’value2’, ‘key3’=’value3’) I tried this in IDLE, but I am getting SyntaxError: expression cannot contain assignment, perhaps you meant "=="?. To confirm if ChatGPT may… Read More Different ways to create dictionary in python
Advertisements I’m trying to check if a combination of two key-value pairs exists in list of dictionaries. Here is my list. data = [ {‘transaction’:’abc123′, ‘stage_one’:’Started’, ‘stage_two’:’Complete’, ‘version’: 12), {‘transaction’:’abc123′, ‘stage_one’:’Started’, ‘stage_two’:’started’, ‘version’: 12), {‘transaction’:’abc123′, ‘stage_one’:’Started’, ‘stage_two’:’processing’, ‘version’: 12), {‘transaction’:’abc123′, ‘stage_one’:’Started’, ‘stage_two’:’Complete’, ‘version’: 12) ] I have tried the below line of code, but I… Read More How to check if two key value pairs exists in list of Dictionary in Python
Advertisements sample_list = [11, 45, 8, 11, 23, 45, 23, 45, 89] print("Original list ", sample_list) count_dict = dict() for item in sample_list: if item in count_dict: count_dict[item] += 1 # how was the data stored into the variable count_dict? else: count_dict[item] = 1 print("Printing count of each item ", count_dict) i just don’t understand… Read More in the below program, i don't understand how was the data stored from the list into the count_dict
Advertisements I am given a text file that is all words with no punctuation, just spaces separating the words. My goal is find and print the word that has the highest frequency in the file along with its frequency. I am able to do this no problem with a similar problem that involves a text… Read More Converting text file to float and into dictionary to find frequency
Advertisements I’m having difficulties trying to get this to work. So to summarize: I have a dataframe, I have a dictionary with keys of certain values in a certain dataframe value, and I want to create a new dataframe column of true/false if they match or not. So here is an example of the data:… Read More Python: If dataframe column matches dictionary key then return boolean for new column
Advertisements I wanted to parse a dictionary with a format. Currently this dictionary has the same user ID in separate dictionaries and I wanted to make it same user ID in one dictionary with key and values. Below is my current dictionary: { "key1": { "userID1": 5, "userID2": 1, "userID3": 5 }, "key2": { "userID1":… Read More Python create parse a dictionary to another format
Advertisements I have a list of dictionaries ls1 = [{‘AccountBalance’: ’78’, ‘Status’: ‘0’}, {‘AccountBalance’: ’56’, ‘Status’: ‘1’}, {‘AccountBalance’: ’34’, ‘Status’: ‘0’}, {‘AccountBalance’: ’12’, ‘Status’: ‘0’}] I would like to convert this to a dictionary of 2 dictionaries dict1 = {‘AccountBalance’: {0: ’78’, 1: ’56’, 2: ’34’, 3: ’12’}, ‘Status’: {0: ‘0’, 1: ‘1’, 2: ‘0’,… Read More Convert list of dictionaries to dictionary of dictionaries
Advertisements I am trying to sort the dictionary based on the value of the first dictionary sequence Example: s = {"J":1, "R":2, "E":3, "L":4] o = {"J":"V140", "E":"21:45", "R":"SUN MON TUE WED THU", "L":"V2730"] expecting the o dictionary in the key order of s o = {"J":"V140","R":"SUN MON TUE WED THU", "E":"21:45", "L":"V2730"} I looked… Read More Sort second dictionary based on value sequence of first