print a list of dict and corresponding key as comma seperated values

I have following dict: data = { ‘A’: [{1.0: 133.0}, {4.0: 126.0}], ‘B’: [{1.0: 153.0}, {4.0: 16.0}], ‘C’: [{1.0: 9.0}, {4.0: 12.0}] } I need the output as follows: A, 1.0, 133.0 A, 4.0, 126.0 B, 1.0, 153.0 B, 4.0, 16.0 C, 1.0, 9.0 C, 4.0, 12.0 This is my attempt (working): with open("super.csv", "w")… Read More print a list of dict and corresponding key as comma seperated values

Create a python dictionary from a .csv file

I have a comma separated file listing the fifty states followed by cities in that state. The structure of the file is as follows: Alabama, Alexander City, Decatur, Florence, Gadsden, Greenville, Guntersville, Huntsville,… Arizona, Ajo, Avondale, Bisbee, Casa Grande, Chandler, Clifton,… Arkansas, Arkadelphia, Arkansas, West Memphis,… California, Alameda, Alhambra, Anaheim, Yorba Linda, Yuba City,… …… Read More Create a python dictionary from a .csv file

Extending Bundle to add extra plist file

I imagine this is going to be simple, but I’m still learning swift. I’ve created a Preferences.plist file that I want to pull in like Info.plist, but separate, ie: Bundle.main.prefsDictionary Or something like that … I have a Bundle+Extension.swift file already, that contains: import Foundation extension Bundle { var releaseVersionNumber: String? { infoDictionary?["CFBundleShortVersionString"] as? String… Read More Extending Bundle to add extra plist file

Flatten nested json file

I have the following json file: { "Teams" : ["Dortmund", "Real Madrid"] , "Countries" : [ "Colombia", { "Italia" : ["Milan", "Inter", "Juventus"] }, { "France" : ["PSG", "Lille"] }, "China" ] } I want to flatten it in a dictionary, so that it looks like this: {"Teams": ["Dortmund", "Real Madrid"], "Countries":["Colombia", "Italia", "Milan", "Inter",… Read More Flatten nested json file

How Would I Use One Dictionary to be a Variable for Another Dictionary's Key Values

So I’m writing a pseudo supply and demand-based Price board for my Python final and I’m having an issue with using one dictionary to influence the values of another. To start, I have a dictionary of various metals I have base costs for. metalDict = { ‘Iron Ingot’: 1, ‘Copper Ingot’:10, ‘Tin Ingot’:30, ‘Silver Ingot’:100,… Read More How Would I Use One Dictionary to be a Variable for Another Dictionary's Key Values

A dict subclass instance is empty after initialization

I try to inherit a dict class, by implementing some logic during the initialization. To do so I add some of the key-value pairs in __init()__ method. However, after initialization, the instance of my child class is always empty. import copy class my_dict(dict): def __init__(self, raw_dict): self = copy.deepcopy(raw_dict) self[‘bar’] = raw_dict[‘foo’] original = {‘foo’… Read More A dict subclass instance is empty after initialization

how to count different keys with conditions in list of dictionaries

I have a list of dicts looks like this: they have different keys in the dicts my_dicts = [ {"id": "1","fixVersion": "1.2.3","releaseDate": "2017-01-21"}, {"id": "2","fixVersion": "2.0", "releaseDate": "2023-01-21"}, {"id": "3","fixVersion": "2.1", "releaseDate": "2023-07-01"}, {"id": "84","changeRequests":"123"} ] I want to count the id if there is "releaseDate" as the key in the dictionaries and also the… Read More how to count different keys with conditions in list of dictionaries

what to do to ignore the output when undefined keys are inputted in python dictionary

the objective is to find the common element of the two array here error comes when dictionary is inputted with values not present in the list A. import numpy as np A=np.random.randint(1,10,15) B=np.random.randint(1,15,15) print(A) print(B) dic={} for x in A: dic[x]=1 for y in B: if dic[y]!=None: print("the common element is ", y) I know… Read More what to do to ignore the output when undefined keys are inputted in python dictionary