How to Construct Method and Attributes using Dictionaries in Python

class print_values: def __init__(self,username,user_email,displayname): self.name= username self.email=user_email self.DisplayName=displayname def printing_content(self): print(f"UserName: {self.name}\n" f"UserEmail: {self.email}\n" f"UserDisplayName:{self.DisplayName}\n") user_one={‘username’:’userone’, ‘useremail’:’userone@gmail.com’, ‘displayname’:’User One’} user_two={‘username’:’usertwo’, ‘useremail’:’usertwo@gmail.com’, ‘displayname’:’User Two’} user_three={‘username’:’userthree’, ‘useremail’:’userthree@gmail.com’, ‘displayname’:’User Three’} users_list=[‘user_one’,’user_two’,’user_three’] obj_name=print_values(user_one[‘username’],user_one[‘useremail’],user_one[‘displayname’]) obj_name.printing_content() It’s working fine, as am getting output as below UserName: userone UserEmail: userone@gmail.com UserDisplayName:User One Here am only using user_one dict, i want to do… Read More How to Construct Method and Attributes using Dictionaries in Python

Effecient conversion of multilevel nested dictionary to df

I looked at several questions but did not find an answer to convert a nested dictionary with this irregular structure: a = {‘Cat0’: {‘brand1’: {‘b’: 0.78, ‘c’: 1}, ‘brand2’: {‘k’: 1, ‘c’: 1}}, ‘Cat1’: {‘brand4’: {‘b’: 10, ‘s’: 0.0}}, ‘Cat2’: {‘brand1’: {‘j’: 1, ‘c’: 0.0}}} to the following pandas dataframe: Category Brand Peer Value 0… Read More Effecient conversion of multilevel nested dictionary to df

Changing specific values in a python dictionary

I have the following dictionary in python: dict={(‘M1 ‘, ‘V1’): 5, (‘M1 ‘, ‘V2’): 5, (‘M1 ‘, ‘V3’): 5, (‘M1 ‘, ‘V4’): 5, (‘M2’, ‘V1’): 5, (‘M2’, ‘V2’): 5, (‘M2’, ‘V3’): 5, (‘M2’, ‘V4’): 5, (‘M3’, ‘V1’): 5, (‘M3’, ‘V2’): 5, (‘M3’, ‘V3’): 5, (‘M3’, ‘V4′): 5} For contextualization, "dict" is a matrix distance ((‘Source’,… Read More Changing specific values in a python dictionary

How to print a list value one below another

I need to sort a ranking of points by descending order. The users and points are inside lista_ranking which includes de following code: [{‘partido’: {‘codigo’: ‘AAA’, ‘fecha’: datetime.date(2022, 11, 20), ‘hora’: ’13:00hs’, ‘equipo_local’: ‘Catar’, ‘equipo_visitante’: ‘Ecuador’, ‘estado’: ‘Finalizado’, ‘goles_local’: 0, ‘goles_visitante’: 1}, ‘usuario’: {‘cedula’: ‘123’, ‘nombre’: ‘Gon’, ‘apellido’: ‘Henderson’, ‘fecha’: ‘(2003, 3, 12)’, ‘puntaje’: 5},… Read More How to print a list value one below another

Append a nested dictionary to a dictionary in python

I’m trying to append a nested dictionary to a dictionary, I have searched the internet and couldn’t find an answer. I tried Colors = {} a = {"1:1":{255,1,2}} b = {"2:1":{1,255,2}} Colors.update(a) Colors.update(b) print(Colors) It prints {‘1:1’: {1, 2, 255}, ‘2:1’: {1, 2, 255}} Instead of {‘1:1’: {255,1,2}, ‘2:1’: {1,255,2}} >Solution : The reason the… Read More Append a nested dictionary to a dictionary in python

Python – Having trouble assigning value into new col based on data from another cell

I have data that looks like; ID File 1 this_file_whatever.ext1 2 this_whatever.ext2 3 this_is_ok_pooh.ext3 I am trying to get the extension and put the key from a dict in a new col based on the extension in File. def create_filegroups(row): filegroup_dict = { ‘GroupA’: ‘ext1’, ‘GroupB’: ‘ext2’, ‘GroupC’: ‘ext3’ } if ‘.’ in row[‘Name’]: test… Read More Python – Having trouble assigning value into new col based on data from another cell