I’m almost familiar with c and c++ programming. Today I was searching about function declaration when I suddenly came across a strange syntax in c++ language. I wrote below code: #include <iostream> using namespace std; int foo(‘3′); int bar(3); int main(){ } I’ve never seen defining the literals as function parameters! So I expected to… Read More Integer literal as parameters of function declaration in cpp

I am new to C and learning it for my University course. I am learning about functions and have to create a function that doesn’t have any printf or scanf in it, just a function that calculates how many days are in a week. int main(days) { int weeks; printf("\nPlease enter a number of weeks:… Read More Why is my function returning 1 and not the variable value?

I want to understand how to know the size of array without using sizeof and not in main function. and i really want to understand why my code not working when i do it in other function.(in main it works same as sizeof). >>> The rasult i got are some trash numbers *with char array… Read More size of array in C without sizeof and not in main function

If I try to compile this small example: void f(const int *a) { int * ptr = a; *ptr = 1; } void g(const int a[]) { int * ptr = a; *ptr = 1; } I get a warning for function f and an error for function g. I tried with gcc 9.3.0 and… Read More Difference between const pointer and const array type in function parameter declaration

I am facing a strange behavior with a char* variable user_message* parseMessage(char *incoming_msg, uint64_t size) { user_message* msg = calloc(1, sizeof(user_message)); printf("value: %s\n", incoming_msg); return msg; } void start_server() { char* msg = "1|david|pwd|"; printf("msg: %s\n", msg); parseMessage(&msg, 12); } The output : msg: 1|david|pwd| value: �[ I struggle to figure out what is wrong… Read More C char* printf issue