I want to take all the elements in the list except the current element. Here is the List:
nums = [1, 1, 3, 5, 2, 3, 4, 4]
I tried using list comprehension:
[(nums[:x:],nums[x+1:]) for x in range(len(nums)) ]
This is the output I am getting:
[([], [1, 3, 5, 2, 3, 4, 4]),
([1], [3, 5, 2, 3, 4, 4]),
([1, 1], [5, 2, 3, 4, 4]),
([1, 1, 3], [2, 3, 4, 4]),
([1, 1, 3, 5], [3, 4, 4]),
([1, 1, 3, 5, 2], [4, 4]),
([1, 1, 3, 5, 2, 3], [4]),
([1, 1, 3, 5, 2, 3, 4], [])]
I am getting two blank lists one in the beginning and one at the end which is correct.
I want to know if there is a way where I can edit these 2 blank lists to [1] by putting any validation?
In essence I need to calculate the product of all the numbers except the current number and I am not allowed to use division.
Also, there is a time constraint that I cannot use nested/multiple for loops as test cases will fail on exceeding time limit
>Solution :
Based on your final goal, it seems like you don’t need two separate lists for before/after the current number. Instead, concatenate them and apply prod. That way you don’t even need to worry about the empty list issue.
from math import prod
nums = [1, 1, 3, 5, 2, 3, 4, 4]
prods = [prod(nums[:i] + nums[i+1:]) for i in range(len(nums))]
print(prods) # [1440, 1440, 480, 288, 720, 480, 360, 360]