Task does not work when with return value with Timeout

I want to create a task to return value that with 5 seconds timeout (desktop application).

Here is my sample code:

public async Task<int> Initialize()
{
    try
    {
        var _result = await (new Task<int>(() =>
        {
            int i = 1;
            ///some code
            return i;
        })).WaitAsync(TimeSpan.FromSeconds(5));
        return _result;
    }
    catch (TimeoutException)
    {
        return -1;
    }
    catch {
        return -2;
    }
}

The framework I am using is .Net8.

Why does the task never start even if I add a break point that always return a TimeoutException.

>Solution :

As you can see right here, task actually executing properly

The only think u need to do, hm so, i guess it is just running this task. Because this is a task btw .-.

After that u should be fine <- This picture

About more information because i use Task.Run() only as example, use in parallel couse a lot of cases needs it: Executing tasks in parallel

Hope it helps