Through proceduraI method want to echo $sql its displaying but some errors are also displaying

<?php

    // Set connection variables
    $server = "localhost";
    $username = "root";
    $password = "";

    // Create a database connection
    $con = mysqli_connect($server, $username, $password);

    // Check for connection success
    if(!$con){
        die("connection to this database failed due to" . mysqli_connect_error());
    }
    // echo "Sucessfully connecting to db";

    // Collect post variables
    $name = $_POST['name'];
    $age= $_POST['age'];
    $gender = $_POST['gender'];
    $email = $_POST['email']; 
    $phone = $_POST['phone'];
    $desc = $_POST['desc'];

    $sql = " INSERT INTO `trip`.`trip` ( `name`, `age`, `gender`, `email`, `phone`, `others`, `dt`) VALUES ( '$name','$age', '$gender', '$email', '$phone','$desc', current_timestamp());";
    
    
     echo $sql; 
 ?>

But Its showing

Warning: Undefined array key "name" in C:\xampp\htdocs\ssm\index.php on line 18

Warning: Undefined array key "age" in C:\xampp\htdocs\ssm\index.php on line 19

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Warning: Undefined array key "gender" in C:\xampp\htdocs\ssm\index.php on line 20

Warning: Undefined array key "email" in C:\xampp\htdocs\ssm\index.php on line 21

Warning: Undefined array key "phone" in C:\xampp\htdocs\ssm\index.php on line 22

Warning: Undefined array key "desc" in C:\xampp\htdocs\ssm\index.php on line 23

INSERT INTO trip . trip ( name, age, gender, email, phone, others, dt) VALUES ( ”,”, ”, ”, ”,”, current_timestamp());

>Solution :

First time your are running this page , there are no post varibales sent to the page , so you get this warnings!
and the other thing to mention is , your code is not executing the SQL command you created , so there is no output for that.