Treat RegEx operator as simple character in java

Ok so I have a String which looks something like this
[RandomChars] Name
and I want to remove the
[RandomChars]
part of the String.

The problem I run in to is that regex treats the [ and ] as operators and not as characters.

I thought adding \\ before the operators would make them act as characters but that doesn’t seem to work.

Here is some sample code

String strOriginal = "[TAS] ElDuko";

String changed = strOriginal.replaceAll("\\[\\D\\]", "");

System.out.println(changed);

>Solution :

You can use

String changed = strOriginal.replaceAll("\\s*\\[[^\\]\\[]*]", "").trim();

See the regex demo and mind the .trim() at the end.

Details:

• \s* – zero or more whitespaces
• \[ – a [ char
• [^\]\[]* – zero or more chars other than [ and ]
• ] – a ] char (it is not special!)