randomgenerator() is a function that yields 6 random integers, the user is prompted to also enter 6 values which are added to lucky[].
I want to compare each yield value to the lucky[] list for a match, but the if condition is not being met.
for x in randomgenerator():
print(f"\n{x} is a winning number.")
if x in lucky:
print(f"There is a match with number {x}")
match.append(x)
def randomgenerator():
for i in range(5):
yield random.randint(1,2)
yield random.randint(1,2)
>Solution :
You said randomgenerator returns a tuple containing ints.
randomgenerator()is a function that yields 6 random values
I guess by "values" you meant integers, since it’s very strange to generate random strings.
Then lucky is filled with input() returned values, which are strings.
if str(x) in lucky: # This should work, since it will convert the int x to a string
a similar solution would be:
lucky = list(map(int, lucky)) # all the elements are converted to integers