Follow

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use
Contact

type alias declaration for function pointer without parameters

From Cppreference – Type alias I know that following type alias declaration works:

using func = void (*) (int, int);

How does the equivalent for a function pointer to a class member look like?

MEDevel.com: Open-source for Healthcare and Education

Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

Visit Medevel

>Solution :

You just need to add a qualifying class name before the *.

For example using func = void (foo::*)(int, int);

Demo :

struct foo
{
    void bar(int, int);
};

using func = void (foo::*)(int, int);

func ptr = &foo::bar;
Add a comment

Leave a Reply

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use

Discover more from Dev solutions

Subscribe now to keep reading and get access to the full archive.

Continue reading