typedef with array in c

Something wrong with my understanding of typedef for arrays in C.
Code just not worked as expected. I provide some screenshot while debugging this simply code. And you can see there, that only firs element of array[0] was assigned right to 0xff. [1] and [2] elements was not assigned.

Exploring assembly code of change_array function, I noticed, that address of array + 0x28 and array + 0x50 was used for assigning [1] and [2] elements. It looks like TMyArray[10][n] was used.

So, I have no idea how to access array elements in function change_array.

    typedef int TMyArray[10];
    TMyArray test_array = {0};

    void change_array(TMyArray * array)
    {
    *array[0] = 0xff;
    *array[1] = 0xff;   // wrong!
    *array[2] = 0xff;   // wring!
    }

    int main()
    {
    change_array(&test_array);
    return 0;
    }

debugger screenshot

I would appreciate any explanation of this behavior.

>Solution :

The unary * has lower precedence than the postfix [] operator, so the expression

*array[1]

is parsed as

*(array[1])

meaning you’re trying to dereference the individual array element, which isn’t what you want. Instead, you need to dereference array first and then index into the result:

(*array)[0] = 0xff;
(*array)[1] = 0xff;
(*array)[2] = 0xff;