Follow

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use
Contact

Typehint a method that returns new instance using a superclass classmethod

from typing import Self, Union


class Superclass:
    @classmethod
    def from_dict(cls, dict_: dict[str, str]) -> Self:
        return cls(**dict_)


class Subclass(Superclass):
    def __init__(self, name: Union[str, None] = None):
        self.name = name

    def copy(self) -> Self:
        return Subclass.from_dict({'name': self.name})

I get an error on the bottom line,

Type "Subclass" is not assignable to return type "Self@Subclass"

I’ve also tried

MEDevel.com: Open-source for Healthcare and Education

Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

Visit Medevel

from typing import Type, TypeVar, Union, Dict

T = TypeVar('T', bound='Superclass')

class Superclass:
    @classmethod
    def from_dict(cls: Type[T], dict_: dict[str, str]) -> T:
        return cls(**dict_)


class Subclass(Superclass):
    def __init__(self, name: Union[str, None] = None):
        self.name = name

    def copy(self: T) -> T:
        return self.from_dict({'name': self.name})

but this one gives me an error

Cannot access attribute "name" for class "Superclass*"   Attribute "name" is unknown


How can I use a superclass’ class method to generate an instance of a child class, inside the child class method?

>Solution :

You’ve got three problems here.

The first problem is that there’s no guarantee the type of self is specifically Subclass. If you call copy on an instance of a subclass of Subclass, then Self is that subclass, and returning an instance of Subclass is wrong.

You need to return an instance of whatever type self is an instance of. The easiest way to do that is to just call from_dict on self or type(self) instead of Subclass:

return self.from_dict({'name': self.name})

…which is exactly what you did in the second version of your code. You fixed this problem! But you introduced a second problem for some reason.

In the second version of your code, you switched to using a type variable T instead of Self. Your T has an upper bound of Superclass rather than Subclass:

T = TypeVar('T', bound='Superclass')

which is okay when you’re using it in Superclass, but in Subclass, it causes the new error. You’d need a second type variable with a Subclass bound if you wanted to go with this approach, but it’d be easier to just use Self.

The third problem is that self.name could be None. You can’t use None as a value of a dict[str, str]. You’ll have to do something about that.

Add a comment

Leave a Reply

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use

Discover more from Dev solutions

Subscribe now to keep reading and get access to the full archive.

Continue reading