typing a phrase and printing a list at anytime in a function

in my function I want to be able to print the following list:

toppings = ["ONION, TOMATO, GREEN PEPPER, MUSHROOM, OLIVE, SPINACH"]

at any time just by typing "X" at any point in my code

>Solution :

You can just use the input() in a while True: loop to get the topping input or the X input.

toppings = ["ONION, TOMATO, GREEN PEPPER, MUSHROOM, OLIVE, SPINACH"] 
added_toppings = []

def chooseToppings(): 
    print("Type in one of our toppings and add it to your pizza. To see the full list of toppings, enter 'X'.") 
    while True:
        x = input()
        if x == "X":
            print(toppings)
        if x == "ONION":
            added_toppings.append("ONION")
        if x == "TOMATO":
            added_toppings.append("TOMATO")
        if x == "GREEN PEPPER":
            added_toppings.append("GREEN PEPPER")
        if x == "MUSHROOM":
            added_toppings.append("MUSHROOM")
        if x == "OLIVE":
            added_toppings.append("OLIVE")
        if x == "SPINACH":
            added_toppings.append("SPINACH")
        if x == "quit":
            break   
    print(added_toppings)

chooseToppings()

It checks every iteration for your input.

If input = "X" it prints the list of toppings.

If input = "TOMATO" it adds "TOMATO" to the added_toppings list.

If input = "quit" it breaks the loop and prints the added_toppings list.