Unix – How can I resolve :command not found

I have 2 scripts test1.sh & test2.sh, below is the defn. for the same

cat test1.sh

DUP_CHK=`beeline --showHeader=false --outputformat=tsv2 -e "select count(*) from table1"`

echo "$DUP_CHK"
export DUP_CHK 

cat test2.sh

#!/bin/bash


source ./test1.sh

cnt_chk="$DUP_CHK"
cnt_chk_2=`beeline --showHeader=false --outputformat=tsv2 -e "select count(*) from table1"`

echo "$DUP_CHK"
echo "$cnt_chk"
echo "$cnt_chk_2"

if "$cnt_chk -eq $cnt_chk_2"
     then
       echo "You are right"
       exit 0
else
    echo "Something is not right, check"
    exit  0
fi

I am passing both value as same but, the error throws as
test2.sh: line 18: 100 -eq 100: command not found

What am I missing here. Thoughts?? Thanks.

>Solution :

You need

  if((cnt_chk == cnt_chk2))