Us image src url in CSS background image url using javascript or jquery

I’m novice at Javascript. I want to use an image src in CSS background image url using javascript.

For example, <img class="user-profile-box-img" src="https://img.freepik.com/free-photo/portrait-young-man-using-mobile-phone-while-standing-outdoors_58466-16294.jpg"/>

This is an image src to show image. I want to use the same image url in css background-image: url(""), so that I don’t need to write twice the same url. How can I do it using javascript or jquery ?

To sum up, I’ll just write image src once inside img tag, and it will automatically add in background-image: url("");

Code Example:

.same-image-div {
    width: 100%;
    margin: auto;
    padding: 60px 15px!important;
background-image: linear-gradient(rgba(38, 70, 235, 0.4), rgba(38, 70, 235, 0.4)),    
url(" here I want the "user-profile-box-img" class image src url ");
    background-position: center;
    background-repeat: no-repeat;
    background-size: cover;
}

.user-profile-box-img{
width: 50%;
margin: auto;
}

<div class="same-image-div">
<img class="user-profile-box-img" src="https://img.freepik.com/free-photo/portrait-young-man-using-mobile-phone-while-standing-outdoors_58466-16294.jpg"/>
</div>

>Solution :

Here is one way to do it using JavaScript:

const img = document.querySelector('.user-profile-box-img');
const div = document.querySelector('.same-image-div');
div.style.backgroundImage = `linear-gradient(rgba(38, 70, 235, 0.4), rgba(38, 70, 235, 0.4)), url(${img.src})`;

Here is one way to do it using jQuery:

const img = $('.user-profile-box-img');
const div = $('.same-image-div');
div.css('background-image', `linear-gradient(rgba(38, 70, 235, 0.4), rgba(38, 70, 235, 0.4)), url(${img.attr('src')})`);