A sequence of positive integers integerList1 and integerList2 are given. All values in each
sequence are different.
Get a set (list of NumberPair values) of all value pairs that satisfy the following conditions:
- the first element of the pair belongs to the sequence integerList1,
- the second belongs to
integerList2 - both elements end with the same digit.
- The NumberPair type includes
Value 1, Value 2 fields. - The resulting NumberPair list must be sorted in ascending order
by the first field, and if they are equal, by the second.
Here is an example:
integerList1: new[] { 1, 12, 4, 5, 78 },
integerList2: new[] { 1, 42, 75, 65, 8, 97 },
expected: new[]
{
new NumberPair{Item1 = 1, Item2 = 1},
new NumberPair{Item1 = 5, Item2 = 65},
new NumberPair{Item1 = 5, Item2 = 75},
new NumberPair{Item1 = 12, Item2 = 42},
new NumberPair{Item1 = 78, Item2 = 8}
});
I tried to solve like this
var lastDigitsGroups1 = integerList1.GroupBy(num => num % 10).ToDictionary(kvp => kvp.Key, kvp => kvp.ToList());
var lastDigitsGroups2 = integerList2.GroupBy(num => num % 10).ToDictionary(kvp => kvp.Key, kvp => kvp.ToList());
var intersection = lastDigitsGroups1.Keys.Intersect(lastDigitsGroups2.Keys);
foreach (var item in intersection)
{
var np = new NumberPair { Item1 = lastDigitsGroups1[item].FirstOrDefault(), Item2 = lastDigitsGroups2[item].FirstOrDefault() };
yield return np;
}
However, it should be done only using LINQ and even with
one LINQ query
>Solution :
Join both lists by keys as below:
var result = (from a in integerList1
join b in integerList2 on (a % 10) equals (b % 10)
select new NumberPair { Item1 = a, Item2 = b }
)
.OrderBy(x => x.Item1)
.ThenBy(x => x.Item2)
.ToList();
Or
var result = integerList1.Join(integerList2,
x => x % 10,
y => y % 10,
(x, y) => new { x, y })
.Select(x => new NumberPair { Item1 = x.x, Item2 = x.y })
.OrderBy(x => x.Item1)
.ThenBy(x => x.Item2)
.ToList();