Use regex to replace words before any digit with nothing

I want to replace words and spaces that appear before a digit in a string with nothing. For example, for the string = ‘Juice of 1/2’, I want to return ‘1/2’. I tried the following, but it did not work.

string = "Juice of 1/2"
new = string.replace(r"^.+?(?=\d)", "")

Also I am trying to perform this on every cell of a list of columns using the following code. How would I incorporate the new regex pattern into the existing pattern of r"(|)|?

df[pd.Index(cols2) + "_clean"] = (
    df[cols2]
    .apply(lambda col: col.str.replace(r"\(|\)|,", "", regex=True))

)

>Solution :

.+? will match anything, including other digits. It will also match the / in 1/2. Since you only want to replace letters and spaces, use [a-z\s]+.

You also have to use re.sub(), not string.replace() (in Pandas, .str.replace() processes regular expressions by default).

new = re.sub(r'[a-z\s]+(?=\d)', '', string, flags=re.I)