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Use REGEX_SUBSTR to get all characters before certain delimiter

byMR
November 29, 2021

I am trying to parse 2021-11-16T04:42:00.000+0000 into 2021-11-16 using REGEX_SUBSTR through SQL on the Snowflake platform.

Any help would be appreciated.

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>Solution :

select left('2021-11-16T04:42:00.000+0000', 10);

output

2021-11-16
byMR
Published
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