User Input of Integers Infinite Loop Until User Inputs a Character (C)
int n = scanf("%d", &i);
if (n == 1) {
can somebody explain me this part I am unable to understand why equality operator does not give false as output and jumps to else statement??
i am a beginner and don’t much about these complicated syntax.
Pls help me
int n = scanf("%d", &i);
if (n == 1) {
if i give 5 as input then value of n will be 5 and when it goes to if statement then (5==1) will execute which will results as false but in this answer it not that case ?
>Solution :
No, that certainly is not the case.
As per the man page:
RETURN VALUE
On success, these functions return the number of input items successfully matched and assigned; this can be fewer than provided for, or even zero, in the event of an early matching failure.
So in the case of a single integer, if scanf was successful in reading and assigning it to a memory address as specified in the second argument, it will returns the number of elements successfully processed.
Aside:
You do not need to declare another variable and assign the return value of scanf to it, you could test for it directly:
if (scanf("%d", &i) != 1) {
..deal with invalid input..
}