Using logical operators with If statements won't output what is expected

I’m starting to learn Python and wrote this:

num1 = int(input('First number '))
num2 = int(input('second number '))
num3 = int(input('third number '))

if num1 > (num2 and num3):
    print(f'{num1:2} is bigger')
    if num2 > num3:
        print(f'{num3:2} is smaller')
    if num3 > num2:
        print(f'{num2:2} is smaller')

if num2 > (num1 and num3):
    print(f'{num2:2} is bigger')
    if num1 > num3:
        print(f'{num3:2} is smaller')
    if num3 > num1:
        print(f'{num1:2} is smaller')
    

if num3 > (num1 and num2):
    print(f'{num3:2} is bigger')
    if num1 > num2:
        print(f'{num2:2} is smaller')
    if num2 > num1:
        print(f'{num1:2} is smaller')

If I enter "5" for the first number "4" for the second and "2" for the third
it outputs:

"5 is bigger
 2 is smaller
 4 is bigger
 2 is smaller"

Why does he reads the line with the false condition statment?

What did I miss?

Also another way to write it would be:

"if num2 > (num1 and num3) and (num1 < num3):
    #print(f'{num2:2} is bigger and {num1:2} is smaller')"

but also didn’t work.

Thanks everyone.

>Solution :

num1 > (num2 and num3)

That doesn’t work how you think it does, you need something like:

num1 > num2 and num1 > num3

# Or if there's lots of them:
num1 > max(num2, num3, num4, num5)

Your current method first calculates num2 and num3 by giving you num2 if it’s false (see below), or num3 otherwise. So 3 > (4 and 2) is the same as 3 > 2, because 4 and 2 is 2. The following transcript illustrates this:

>>> print(0 and 99)
0
>>> print(1 and 99)
99
>>> print(2 and 99)
99
>>> print(-1 and 99)
99

Basically, numbers are considered false if they’re zero, hence the output shown above.

As an aside, you may also want to think about what will happen if two or more of the numbers are equal.