Follow

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use
Contact

Using pandas nullable integer dtype in np.where condition

I have a DataFrame below which has some missing values.

df = pd.DataFrame(data=[['A', 1, None], ['B', 2, 5]],
                  columns=['X', 'Y', 'Z'])

Since df['Z'] is supposed to be an integer column, I changed its data type to pandas new experimental type nullable integer as below.

ydf['Z'] = ydf['Z'].astype(pd.Int32Dtype())
ydf

    X   Y   Z
0   A   1   <NA>
1   B   2   5

Now I am trying to use a simple numpy where method to replace the non-null values in the column df['Z'] with a fixed integer value (say 1) using the code below.

MEDevel.com: Open-source for Healthcare and Education

Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

Visit Medevel

np.where(pd.isna(ydf['Z']), pd.NA, np.where(ydf['Z'] > 0, 1, 0))

But I get the following error, and I am unable to understand why as I am already checking for the rows with null values in the first condition.

TypeError: boolean value of NA is ambiguous

>Solution :

np.where expects an array of booleans. With the int64 dtype, using > on the Series returns False for nans. With the Int32 dtype (note the capital I), > doesn’t coerce nans to False, thus the error.

One solution would be to use ydf['Z'].gt(0).fillna(False) instead of ydf['Z'] > 0. (They’re the same, the second one just changes NA to False):

np.where(pd.isna(ydf['Z']), pd.NA, np.where(ydf['Z'].gt(0).fillna(False), 1, 0))
Add a comment

Leave a Reply

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use

Discover more from Dev solutions

Subscribe now to keep reading and get access to the full archive.

Continue reading