Using REGEXP_LIKE in IF condition is throwing error at 'END IF;'

I am trying to use REGEXP_LIKE function in IF.

IF REGEXP_LIKE('NUM','^\\d{11}$')
  THEN
    BEGIN
     <My code>
    END
END IF;

Error coming at END IF is:

Syntax error. Partially recognized rules.

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Please advise where I am going wrong.

>Solution :

You are getting an error because you are missing a semicolon after END within your IF statement. Below is an example of valid code:

BEGIN
    IF REGEXP_LIKE ('NUM', '^\\d{11}$')
    THEN
        BEGIN
            --Some code here
            NULL;
        END;

        --More code here
        NULL;
    END IF;
END;