I’m learning Rust and have been going through leetcode problems. One of them includes merging two linked lists, whose nodes are optional. I want to write a while loop that would go on until at least 1 node becomes None, and I was trying to use the while let loop for that.
However, it looks like the while let syntax supports only one optional, e.g.:
while let Some(n) = node {
// do stuff
}
but I can’t write
while let Some(n1) = node1 && Some(n2) = node2 {
}
Am I misunderstanding the syntax? I know I can rewrite it with a while true loop, but is there a more elegant way of doing it?
Also, can one do multiple checks with if let? Like if let None=node1 && None=node2 {return}
>Solution :
You can pattern match with Option::zip:
while let Some((n1, n2)) = node1.zip(node2) {
...
}