Verify User Input is a number only on Fibonacci sequence

import java.util.Scanner;

public class Fibonacci {
public static void main(String args[]) {


    
    int result = UserInput();

    fibArray[0] = 1;
    fibArray[1] = 1;

    for (int i = 0; i < result; i++)


        System.out.print(fibonacci(i) + " ");

}


public static long fibArray[] = new long[1000];

public static long fibonacci(long n) {
    long fibValue = 0;
    if (n == 0) {
        return 0;
    } else if (n == 1) {
        return 1;

    } else if (fibArray[(int) n] != 0) {
        return fibArray[(int) n];
    } else {
        fibValue = fibonacci(n - 1) + fibonacci(n - 2);
        fibArray[(int) n] = fibValue;
        return fibValue;
    }
}

public static int UserInput() {

    System.out.print("Enter a Fibonacci Number ");
    Scanner test = new Scanner(System.in);
    int n = test.nextInt();
   

    return n;
}
}

Hi This is not homework nor is it a college assignment. I’m just learning java and I would like to implement a check in my UserInput method on Fibonacci sequence, I want only numbers to be entered and not special characters or letters. I’ve read other similar topics here but
I’m still a bit unsure as to how to do this.

How would I achieve this ?

And btw sorry if the code is sloppy.
Thanks

>Solution :

To check if an entered value is part of a fibonacci series

• first add a set to add the fibValue in your method where you add it to the long array

public static Set<Long> fibSet = new HashSet<>();

• then do the following:

    int value = UserInput();
    boolean has = fibSet.contains(value);
    for (int i = 0; i < 1000 && has == false; i++) {
        if (value == fibonacci(i)) {
            has = true;
            break;
        }
    }
    System.out.println(value + " is" + (has ? "" : " not")
            + " a term in the standard fibonacci sequence");
  

  }