What does char* assignment do?

I have a char* and I’m assigning another char* to it. I want to know what all is going to happen through that instruction?

For example:

char* foo; // suppose it is initialized and defined

char* bar = foo // I am defining bar

What all would happen(to foo and bar) after calling the assignment operation wrt values, memory etc.

I am new to C, maybe very trivial question for some of you.

>Solution :

Lets say we have two pointers initialized to point to different strings:

const char *foo = "abcd";
const char *bar = "efgh";

If we "draw" how they would look in memory, it would be something like this:

+-----+      +--------+
| foo | ---> | "abcd" |
+-----+      +--------+

+-----+      +--------+
| bar | ---> | "efgh" |
+-----+      +--------+

Then we assign to bar:

bar = foo;

Then it would look something like this instead:

+-----+      +--------+
| foo | -+-> | "abcd" |
+-----+  |   +--------+
         |
+-----+  |   +--------+
| bar | -/   | "efgh" |
+-----+      +--------+

Now both foo and bar are pointing to the same location.

In shorter form, that’s what a definition with initialization like:

const char *bar = foo;

will do.